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Arătați că : logaritm in baza 2 din 3 > logaritm in baza 3 din 4 - Brainly.ro
Log1000, log(128/625), log(x²y³z⁴), log(p²q³/r), log√(x³/y²) write in expanded form... - YouTube
7 = log2 128, write in exponential form - YouTube
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x=log in baza 7 din 2; a= log in baza 2 din 21; b=log in baza 2 din 6.Calculati x in functie de a si b - Brainly.ro
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Determine the value of log128 to the base 8 (LOGARITHM-022) - YouTube
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Proprietatile logaritmilor. Formule. Operatii -log, ln, lg (exercitii rezolvate matematica clasa a 10 a) – #JitaruIonelBLOG -pregatire BAC si Evaluarea Nationala 2023 la matematica si alte materii! *materiale (lectii +formule +exercitii rezolvate
SOLVED:Simplify: log64-log128+log32. 64=2^6, 128=2^7 and 32=2^5 Hence, log64-log128+log32 =log2^6-log2^7+log2^5 =6 log2-7 log2+5 log2 by the third law of logarithms =4 log2
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Log în baza 2 din 3 = ? Log în baza 2 din 6 = ? Îmi puteţi explica, vă rog? - Brainly.ro
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